6(x+2)+4(x-1)=3(2x+5)-8

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Solution for 6(x+2)+4(x-1)=3(2x+5)-8 equation: 



6(x+2)+4(x-1)=3(2x+5)-8

We move all terms to the left:

6(x+2)+4(x-1)-(3(2x+5)-8)=0

We multiply parentheses

6x+4x-(3(2x+5)-8)+12-4=0



We calculate terms in parentheses: -(3(2x+5)-8), so:

3(2x+5)-8

We multiply parentheses

6x+15-8

We add all the numbers together, and all the variables

6x+7

Back to the equation:

-(6x+7)



We add all the numbers together, and all the variables

10x-(6x+7)+8=0

We get rid of parentheses

10x-6x-7+8=0

We add all the numbers together, and all the variables

4x+1=0

We move all terms containing x to the left, all other terms to the right

4x=-1

x=-1/4

x=-1/4

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