6(x+2)+4(x-1)=8(x+3)+10

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Solution for 6(x+2)+4(x-1)=8(x+3)+10 equation: 



6(x+2)+4(x-1)=8(x+3)+10

We move all terms to the left:

6(x+2)+4(x-1)-(8(x+3)+10)=0

We multiply parentheses

6x+4x-(8(x+3)+10)+12-4=0



We calculate terms in parentheses: -(8(x+3)+10), so:

8(x+3)+10

We multiply parentheses

8x+24+10

We add all the numbers together, and all the variables

8x+34

Back to the equation:

-(8x+34)



We add all the numbers together, and all the variables

10x-(8x+34)+8=0

We get rid of parentheses

10x-8x-34+8=0

We add all the numbers together, and all the variables

2x-26=0

We move all terms containing x to the left, all other terms to the right

2x=26

x=26/2

x=13

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