6(x+2)+8(3-x)=30

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Solution for 6(x+2)+8(3-x)=30 equation:



6(x+2)+8(3-x)=30
We move all terms to the left:
6(x+2)+8(3-x)-(30)=0
We add all the numbers together, and all the variables
6(x+2)+8(-1x+3)-30=0
We multiply parentheses
6x-8x+12+24-30=0
We add all the numbers together, and all the variables
-2x+6=0
We move all terms containing x to the left, all other terms to the right
-2x=-6
x=-6/-2
x=+3

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