6(x+2)+x=2(x+3)+6

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Solution for 6(x+2)+x=2(x+3)+6 equation: 



6(x+2)+x=2(x+3)+6

We move all terms to the left:

6(x+2)+x-(2(x+3)+6)=0

We add all the numbers together, and all the variables

x+6(x+2)-(2(x+3)+6)=0

We multiply parentheses

x+6x-(2(x+3)+6)+12=0



We calculate terms in parentheses: -(2(x+3)+6), so:

2(x+3)+6

We multiply parentheses

2x+6+6

We add all the numbers together, and all the variables

2x+12

Back to the equation:

-(2x+12)



We add all the numbers together, and all the variables

7x-(2x+12)+12=0

We get rid of parentheses

7x-2x-12+12=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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