6(x+2)+x=4(x+4)+2

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Solution for 6(x+2)+x=4(x+4)+2 equation: 



6(x+2)+x=4(x+4)+2

We move all terms to the left:

6(x+2)+x-(4(x+4)+2)=0

We add all the numbers together, and all the variables

x+6(x+2)-(4(x+4)+2)=0

We multiply parentheses

x+6x-(4(x+4)+2)+12=0



We calculate terms in parentheses: -(4(x+4)+2), so:

4(x+4)+2

We multiply parentheses

4x+16+2

We add all the numbers together, and all the variables

4x+18

Back to the equation:

-(4x+18)



We add all the numbers together, and all the variables

7x-(4x+18)+12=0

We get rid of parentheses

7x-4x-18+12=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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