6(x+2)-(9x-1)=2(3x+3)+3

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Solution for 6(x+2)-(9x-1)=2(3x+3)+3 equation: 



6(x+2)-(9x-1)=2(3x+3)+3

We move all terms to the left:

6(x+2)-(9x-1)-(2(3x+3)+3)=0

We multiply parentheses

6x-(9x-1)-(2(3x+3)+3)+12=0

We get rid of parentheses

6x-9x-(2(3x+3)+3)+1+12=0



We calculate terms in parentheses: -(2(3x+3)+3), so:

2(3x+3)+3

We multiply parentheses

6x+6+3

We add all the numbers together, and all the variables

6x+9

Back to the equation:

-(6x+9)



We add all the numbers together, and all the variables

-3x-(6x+9)+13=0

We get rid of parentheses

-3x-6x-9+13=0

We add all the numbers together, and all the variables

-9x+4=0

We move all terms containing x to the left, all other terms to the right

-9x=-4

x=-4/-9

x=4/9

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