6(x+2)-(x-5)4=(2x-5)3+2(x+3)-(x+1)

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Solution for 6(x+2)-(x-5)4=(2x-5)3+2(x+3)-(x+1) equation: 



6(x+2)-(x-5)4=(2x-5)3+2(x+3)-(x+1)

We move all terms to the left:

6(x+2)-(x-5)4-((2x-5)3+2(x+3)-(x+1))=0

We multiply parentheses

6x-4x-((2x-5)3+2(x+3)-(x+1))+12+20=0



We calculate terms in parentheses: -((2x-5)3+2(x+3)-(x+1)), so:

(2x-5)3+2(x+3)-(x+1)

We multiply parentheses

6x+2x-(x+1)-15+6

We get rid of parentheses

6x+2x-x-1-15+6

We add all the numbers together, and all the variables

7x-10

Back to the equation:

-(7x-10)



We add all the numbers together, and all the variables

2x-(7x-10)+32=0

We get rid of parentheses

2x-7x+10+32=0

We add all the numbers together, and all the variables

-5x+42=0

We move all terms containing x to the left, all other terms to the right

-5x=-42

x=-42/-5

x=8+2/5

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