6(x+2)-2=4(x+4)=7

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Solution for 6(x+2)-2=4(x+4)=7 equation: 



6(x+2)-2=4(x+4)=7

We move all terms to the left:

6(x+2)-2-(4(x+4))=0

We multiply parentheses

6x-(4(x+4))+12-2=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

6x-(4x+16)+10=0

We get rid of parentheses

6x-4x-16+10=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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