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6(x+2)-2x=4(x-3)
We move all terms to the left:
6(x+2)-2x-(4(x-3))=0
We add all the numbers together, and all the variables
-2x+6(x+2)-(4(x-3))=0
We multiply parentheses
-2x+6x-(4(x-3))+12=0
We calculate terms in parentheses: -(4(x-3)), so:We add all the numbers together, and all the variables
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
4x-(4x-12)+12=0
We get rid of parentheses
4x-4x+12+12=0
We add all the numbers together, and all the variables
24!=0
There is no solution for this equation
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