6(x+2)-3=2x+4(1+x)

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Solution for 6(x+2)-3=2x+4(1+x) equation: 



6(x+2)-3=2x+4(1+x)

We move all terms to the left:

6(x+2)-3-(2x+4(1+x))=0

We add all the numbers together, and all the variables

6(x+2)-(2x+4(x+1))-3=0

We multiply parentheses

6x-(2x+4(x+1))+12-3=0



We calculate terms in parentheses: -(2x+4(x+1)), so:

2x+4(x+1)

We multiply parentheses

2x+4x+4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

6x-(6x+4)+9=0

We get rid of parentheses

6x-6x-4+9=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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