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6(x+2)-3=3x+3(3+x)
We move all terms to the left:
6(x+2)-3-(3x+3(3+x))=0
We add all the numbers together, and all the variables
6(x+2)-(3x+3(x+3))-3=0
We multiply parentheses
6x-(3x+3(x+3))+12-3=0
We calculate terms in parentheses: -(3x+3(x+3)), so:We add all the numbers together, and all the variables
3x+3(x+3)
We multiply parentheses
3x+3x+9
We add all the numbers together, and all the variables
6x+9
Back to the equation:
-(6x+9)
6x-(6x+9)+9=0
We get rid of parentheses
6x-6x-9+9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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