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6(x+2)-3=9+x
We move all terms to the left:
6(x+2)-3-(9+x)=0
We add all the numbers together, and all the variables
6(x+2)-(x+9)-3=0
We multiply parentheses
6x-(x+9)+12-3=0
We get rid of parentheses
6x-x-9+12-3=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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