6(x+2)-3x-4=2(x+2)

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Solution for 6(x+2)-3x-4=2(x+2) equation: 



6(x+2)-3x-4=2(x+2)

We move all terms to the left:

6(x+2)-3x-4-(2(x+2))=0

We add all the numbers together, and all the variables

-3x+6(x+2)-(2(x+2))-4=0

We multiply parentheses

-3x+6x-(2(x+2))+12-4=0



We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

3x-(2x+4)+8=0

We get rid of parentheses

3x-2x-4+8=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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