6(x+2)-4(2x+3)=32

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Solution for 6(x+2)-4(2x+3)=32 equation: 



6(x+2)-4(2x+3)=32

We move all terms to the left:

6(x+2)-4(2x+3)-(32)=0

We multiply parentheses

6x-8x+12-12-32=0

We add all the numbers together, and all the variables

-2x-32=0

We move all terms containing x to the left, all other terms to the right

-2x=32

x=32/-2

x=-16

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