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6(x+2)-4=2x+4(1+x)
We move all terms to the left:
6(x+2)-4-(2x+4(1+x))=0
We add all the numbers together, and all the variables
6(x+2)-(2x+4(x+1))-4=0
We multiply parentheses
6x-(2x+4(x+1))+12-4=0
We calculate terms in parentheses: -(2x+4(x+1)), so:We add all the numbers together, and all the variables
2x+4(x+1)
We multiply parentheses
2x+4x+4
We add all the numbers together, and all the variables
6x+4
Back to the equation:
-(6x+4)
6x-(6x+4)+8=0
We get rid of parentheses
6x-6x-4+8=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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