6(x+2)-x=4(x+4)+

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Solution for 6(x+2)-x=4(x+4)+ equation: 



6(x+2)-x=4(x+4)+

We move all terms to the left:

6(x+2)-x-(4(x+4)+)=0

We add all the numbers together, and all the variables

-1x+6(x+2)-(4(x+4)+)=0

We multiply parentheses

-1x+6x-(4(x+4)+)+12=0



We calculate terms in parentheses: -(4(x+4)+), so:

4(x+4)+

We add all the numbers together, and all the variables

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

5x-(4x+16)+12=0

We get rid of parentheses

5x-4x-16+12=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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