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6(x+2)-x=4(x-4)=7
We move all terms to the left:
6(x+2)-x-(4(x-4))=0
We add all the numbers together, and all the variables
-1x+6(x+2)-(4(x-4))=0
We multiply parentheses
-1x+6x-(4(x-4))+12=0
We calculate terms in parentheses: -(4(x-4)), so:We add all the numbers together, and all the variables
4(x-4)
We multiply parentheses
4x-16
Back to the equation:
-(4x-16)
5x-(4x-16)+12=0
We get rid of parentheses
5x-4x+16+12=0
We add all the numbers together, and all the variables
x+28=0
We move all terms containing x to the left, all other terms to the right
x=-28
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