6(x+2)2x-4=8(x-2)+2

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Solution for 6(x+2)2x-4=8(x-2)+2 equation: 



6(x+2)2x-4=8(x-2)+2

We move all terms to the left:

6(x+2)2x-4-(8(x-2)+2)=0

We multiply parentheses

12x^2+24x-(8(x-2)+2)-4=0



We calculate terms in parentheses: -(8(x-2)+2), so:

8(x-2)+2

We multiply parentheses

8x-16+2

We add all the numbers together, and all the variables

8x-14

Back to the equation:

-(8x-14)



We get rid of parentheses

12x^2+24x-8x+14-4=0

We add all the numbers together, and all the variables

12x^2+16x+10=0

a = 12; b = 16; c = +10;
Δ = b2-4ac
Δ = 162-4·12·10
Δ = -224
Delta is less than zero, so there is no solution for the equation

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