6(x+2)=(8x-20)/2

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Solution for 6(x+2)=(8x-20)/2 equation: 



6(x+2)=(8x-20)/2

We move all terms to the left:

6(x+2)-((8x-20)/2)=0

We multiply parentheses

6x-((8x-20)/2)+12=0

We multiply all the terms by the denominator


6x*2)-((8x-20)+12*2)=0

We add all the numbers together, and all the variables

6x*2)-((8x-20)=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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