6(x+2)=-2(8x-2)+8x

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Solution for 6(x+2)=-2(8x-2)+8x equation: 



6(x+2)=-2(8x-2)+8x

We move all terms to the left:

6(x+2)-(-2(8x-2)+8x)=0

We multiply parentheses

6x-(-2(8x-2)+8x)+12=0



We calculate terms in parentheses: -(-2(8x-2)+8x), so:

-2(8x-2)+8x

We add all the numbers together, and all the variables

8x-2(8x-2)

We multiply parentheses

8x-16x+4

We add all the numbers together, and all the variables

-8x+4

Back to the equation:

-(-8x+4)



We get rid of parentheses

6x+8x-4+12=0

We add all the numbers together, and all the variables

14x+8=0

We move all terms containing x to the left, all other terms to the right

14x=-8

x=-8/14

x=-4/7

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