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6(x+2)=2(5x-4)
We move all terms to the left:
6(x+2)-(2(5x-4))=0
We multiply parentheses
6x-(2(5x-4))+12=0
We calculate terms in parentheses: -(2(5x-4)), so:We get rid of parentheses
2(5x-4)
We multiply parentheses
10x-8
Back to the equation:
-(10x-8)
6x-10x+8+12=0
We add all the numbers together, and all the variables
-4x+20=0
We move all terms containing x to the left, all other terms to the right
-4x=-20
x=-20/-4
x=+5
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