6(x+2)=3(2-x)

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Solution for 6(x+2)=3(2-x) equation: 



6(x+2)=3(2-x)

We move all terms to the left:

6(x+2)-(3(2-x))=0

We add all the numbers together, and all the variables

6(x+2)-(3(-1x+2))=0

We multiply parentheses

6x-(3(-1x+2))+12=0



We calculate terms in parentheses: -(3(-1x+2)), so:

3(-1x+2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We get rid of parentheses

6x+3x-6+12=0

We add all the numbers together, and all the variables

9x+6=0

We move all terms containing x to the left, all other terms to the right

9x=-6

x=-6/9

x=-2/3

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