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6(x+2)=3(2x+12)
We move all terms to the left:
6(x+2)-(3(2x+12))=0
We multiply parentheses
6x-(3(2x+12))+12=0
We calculate terms in parentheses: -(3(2x+12)), so:We get rid of parentheses
3(2x+12)
We multiply parentheses
6x+36
Back to the equation:
-(6x+36)
6x-6x-36+12=0
We add all the numbers together, and all the variables
-24!=0
There is no solution for this equation
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