6(x+2)=3(2x+5)-3

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Solution for 6(x+2)=3(2x+5)-3 equation: 



6(x+2)=3(2x+5)-3

We move all terms to the left:

6(x+2)-(3(2x+5)-3)=0

We multiply parentheses

6x-(3(2x+5)-3)+12=0



We calculate terms in parentheses: -(3(2x+5)-3), so:

3(2x+5)-3

We multiply parentheses

6x+15-3

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

6x-6x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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