6(x+2)=3(4+3)=144

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Solution for 6(x+2)=3(4+3)=144 equation: 



6(x+2)=3(4+3)=144

We move all terms to the left:

6(x+2)-(3(4+3))=0

We add all the numbers together, and all the variables

6(x+2)-(37)=0

We add all the numbers together, and all the variables

6(x+2)-37=0

We multiply parentheses

6x+12-37=0

We add all the numbers together, and all the variables

6x-25=0

We move all terms containing x to the left, all other terms to the right

6x=25

x=25/6

x=4+1/6

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