6(x+2)=3(4x-1)-3

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Solution for 6(x+2)=3(4x-1)-3 equation: 



6(x+2)=3(4x-1)-3

We move all terms to the left:

6(x+2)-(3(4x-1)-3)=0

We multiply parentheses

6x-(3(4x-1)-3)+12=0



We calculate terms in parentheses: -(3(4x-1)-3), so:

3(4x-1)-3

We multiply parentheses

12x-3-3

We add all the numbers together, and all the variables

12x-6

Back to the equation:

-(12x-6)



We get rid of parentheses

6x-12x+6+12=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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