6(x+2)=4(x+12)

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Solution for 6(x+2)=4(x+12) equation: 



6(x+2)=4(x+12)

We move all terms to the left:

6(x+2)-(4(x+12))=0

We multiply parentheses

6x-(4(x+12))+12=0



We calculate terms in parentheses: -(4(x+12)), so:

4(x+12)

We multiply parentheses

4x+48

Back to the equation:

-(4x+48)



We get rid of parentheses

6x-4x-48+12=0

We add all the numbers together, and all the variables

2x-36=0

We move all terms containing x to the left, all other terms to the right

2x=36

x=36/2

x=18

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