6(x+2)=4(x-3)+5

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Solution for 6(x+2)=4(x-3)+5 equation: 



6(x+2)=4(x-3)+5

We move all terms to the left:

6(x+2)-(4(x-3)+5)=0

We multiply parentheses

6x-(4(x-3)+5)+12=0



We calculate terms in parentheses: -(4(x-3)+5), so:

4(x-3)+5

We multiply parentheses

4x-12+5

We add all the numbers together, and all the variables

4x-7

Back to the equation:

-(4x-7)



We get rid of parentheses

6x-4x+7+12=0

We add all the numbers together, and all the variables

2x+19=0

We move all terms containing x to the left, all other terms to the right

2x=-19

x=-19/2

x=-9+1/2

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