6(x+2)=7(x-5)

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Solution for 6(x+2)=7(x-5) equation: 



6(x+2)=7(x-5)

We move all terms to the left:

6(x+2)-(7(x-5))=0

We multiply parentheses

6x-(7(x-5))+12=0



We calculate terms in parentheses: -(7(x-5)), so:

7(x-5)

We multiply parentheses

7x-35

Back to the equation:

-(7x-35)



We get rid of parentheses

6x-7x+35+12=0

We add all the numbers together, and all the variables

-1x+47=0

We move all terms containing x to the left, all other terms to the right

-x=-47

x=-47/-1

x=+47

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