6(x+2)=9x-3(2x-1)

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Solution for 6(x+2)=9x-3(2x-1) equation: 



6(x+2)=9x-3(2x-1)

We move all terms to the left:

6(x+2)-(9x-3(2x-1))=0

We multiply parentheses

6x-(9x-3(2x-1))+12=0



We calculate terms in parentheses: -(9x-3(2x-1)), so:

9x-3(2x-1)

We multiply parentheses

9x-6x+3

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

6x-3x-3+12=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

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