6(x+20)=24+3(x-2)

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Solution for 6(x+20)=24+3(x-2) equation: 



6(x+20)=24+3(x-2)

We move all terms to the left:

6(x+20)-(24+3(x-2))=0

We multiply parentheses

6x-(24+3(x-2))+120=0



We calculate terms in parentheses: -(24+3(x-2)), so:

24+3(x-2)

determiningTheFunctionDomain
3(x-2)+24

We multiply parentheses

3x-6+24

We add all the numbers together, and all the variables

3x+18

Back to the equation:

-(3x+18)



We get rid of parentheses

6x-3x-18+120=0

We add all the numbers together, and all the variables

3x+102=0

We move all terms containing x to the left, all other terms to the right

3x=-102

x=-102/3

x=-34

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