6(x+3)+10=2(3x-4)

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Solution for 6(x+3)+10=2(3x-4) equation:


Simplifying
6(x + 3) + 10 = 2(3x + -4)

Reorder the terms:
6(3 + x) + 10 = 2(3x + -4)
(3 * 6 + x * 6) + 10 = 2(3x + -4)
(18 + 6x) + 10 = 2(3x + -4)

Reorder the terms:
18 + 10 + 6x = 2(3x + -4)

Combine like terms: 18 + 10 = 28
28 + 6x = 2(3x + -4)

Reorder the terms:
28 + 6x = 2(-4 + 3x)
28 + 6x = (-4 * 2 + 3x * 2)
28 + 6x = (-8 + 6x)

Add '-6x' to each side of the equation.
28 + 6x + -6x = -8 + 6x + -6x

Combine like terms: 6x + -6x = 0
28 + 0 = -8 + 6x + -6x
28 = -8 + 6x + -6x

Combine like terms: 6x + -6x = 0
28 = -8 + 0
28 = -8

Solving
28 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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