6(x+3)+2=-11(x-11)-10

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Solution for 6(x+3)+2=-11(x-11)-10 equation: 



6(x+3)+2=-11(x-11)-10

We move all terms to the left:

6(x+3)+2-(-11(x-11)-10)=0

We multiply parentheses

6x-(-11(x-11)-10)+18+2=0



We calculate terms in parentheses: -(-11(x-11)-10), so:

-11(x-11)-10

We multiply parentheses

-11x+121-10

We add all the numbers together, and all the variables

-11x+111

Back to the equation:

-(-11x+111)



We add all the numbers together, and all the variables

6x-(-11x+111)+20=0

We get rid of parentheses

6x+11x-111+20=0

We add all the numbers together, and all the variables

17x-91=0

We move all terms containing x to the left, all other terms to the right

17x=91

x=91/17

x=5+6/17

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