6(x+3)+2=-6(x-1)-1

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Solution for 6(x+3)+2=-6(x-1)-1 equation: 



6(x+3)+2=-6(x-1)-1

We move all terms to the left:

6(x+3)+2-(-6(x-1)-1)=0

We multiply parentheses

6x-(-6(x-1)-1)+18+2=0



We calculate terms in parentheses: -(-6(x-1)-1), so:

-6(x-1)-1

We multiply parentheses

-6x+6-1

We add all the numbers together, and all the variables

-6x+5

Back to the equation:

-(-6x+5)



We add all the numbers together, and all the variables

6x-(-6x+5)+20=0

We get rid of parentheses

6x+6x-5+20=0

We add all the numbers together, and all the variables

12x+15=0

We move all terms containing x to the left, all other terms to the right

12x=-15

x=-15/12

x=-1+1/4

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