6(x+3)+2=5(1-x)+8

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Solution for 6(x+3)+2=5(1-x)+8 equation: 



6(x+3)+2=5(1-x)+8

We move all terms to the left:

6(x+3)+2-(5(1-x)+8)=0

We add all the numbers together, and all the variables

6(x+3)-(5(-1x+1)+8)+2=0

We multiply parentheses

6x-(5(-1x+1)+8)+18+2=0



We calculate terms in parentheses: -(5(-1x+1)+8), so:

5(-1x+1)+8

We multiply parentheses

-5x+5+8

We add all the numbers together, and all the variables

-5x+13

Back to the equation:

-(-5x+13)



We add all the numbers together, and all the variables

6x-(-5x+13)+20=0

We get rid of parentheses

6x+5x-13+20=0

We add all the numbers together, and all the variables

11x+7=0

We move all terms containing x to the left, all other terms to the right

11x=-7

x=-7/11

x=-7/11

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