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6(x+3)+2x=4(2x+1)
We move all terms to the left:
6(x+3)+2x-(4(2x+1))=0
We add all the numbers together, and all the variables
2x+6(x+3)-(4(2x+1))=0
We multiply parentheses
2x+6x-(4(2x+1))+18=0
We calculate terms in parentheses: -(4(2x+1)), so:We add all the numbers together, and all the variables
4(2x+1)
We multiply parentheses
8x+4
Back to the equation:
-(8x+4)
8x-(8x+4)+18=0
We get rid of parentheses
8x-8x-4+18=0
We add all the numbers together, and all the variables
14!=0
There is no solution for this equation
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