6(x+3)+2x=4x+22

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Solution for 6(x+3)+2x=4x+22 equation:



6(x+3)+2x=4x+22
We move all terms to the left:
6(x+3)+2x-(4x+22)=0
We add all the numbers together, and all the variables
2x+6(x+3)-(4x+22)=0
We multiply parentheses
2x+6x-(4x+22)+18=0
We get rid of parentheses
2x+6x-4x-22+18=0
We add all the numbers together, and all the variables
4x-4=0
We move all terms containing x to the left, all other terms to the right
4x=4
x=4/4
x=1

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