6(x+3)+2x=4x+22

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Solution for 6(x+3)+2x=4x+22 equation: 



6(x+3)+2x=4x+22

We move all terms to the left:

6(x+3)+2x-(4x+22)=0

We add all the numbers together, and all the variables

2x+6(x+3)-(4x+22)=0

We multiply parentheses

2x+6x-(4x+22)+18=0

We get rid of parentheses

2x+6x-4x-22+18=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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