6(x+3)+4x=2(3x-4)+12

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Solution for 6(x+3)+4x=2(3x-4)+12 equation: 



6(x+3)+4x=2(3x-4)+12

We move all terms to the left:

6(x+3)+4x-(2(3x-4)+12)=0

We add all the numbers together, and all the variables

4x+6(x+3)-(2(3x-4)+12)=0

We multiply parentheses

4x+6x-(2(3x-4)+12)+18=0



We calculate terms in parentheses: -(2(3x-4)+12), so:

2(3x-4)+12

We multiply parentheses

6x-8+12

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

10x-(6x+4)+18=0

We get rid of parentheses

10x-6x-4+18=0

We add all the numbers together, and all the variables

4x+14=0

We move all terms containing x to the left, all other terms to the right

4x=-14

x=-14/4

x=-3+1/2

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