6(x+3)+x=4(x+2)+1

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Solution for 6(x+3)+x=4(x+2)+1 equation: 



6(x+3)+x=4(x+2)+1

We move all terms to the left:

6(x+3)+x-(4(x+2)+1)=0

We add all the numbers together, and all the variables

x+6(x+3)-(4(x+2)+1)=0

We multiply parentheses

x+6x-(4(x+2)+1)+18=0



We calculate terms in parentheses: -(4(x+2)+1), so:

4(x+2)+1

We multiply parentheses

4x+8+1

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We add all the numbers together, and all the variables

7x-(4x+9)+18=0

We get rid of parentheses

7x-4x-9+18=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

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