6(x+3)+x=4(x+4)+7

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Solution for 6(x+3)+x=4(x+4)+7 equation:



6(x+3)+x=4(x+4)+7
We move all terms to the left:
6(x+3)+x-(4(x+4)+7)=0
We add all the numbers together, and all the variables
x+6(x+3)-(4(x+4)+7)=0
We multiply parentheses
x+6x-(4(x+4)+7)+18=0
We calculate terms in parentheses: -(4(x+4)+7), so:
4(x+4)+7
We multiply parentheses
4x+16+7
We add all the numbers together, and all the variables
4x+23
Back to the equation:
-(4x+23)
We add all the numbers together, and all the variables
7x-(4x+23)+18=0
We get rid of parentheses
7x-4x-23+18=0
We add all the numbers together, and all the variables
3x-5=0
We move all terms containing x to the left, all other terms to the right
3x=5
x=5/3
x=1+2/3

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