6(x+3)-12=4(x-2)

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Solution for 6(x+3)-12=4(x-2) equation: 



6(x+3)-12=4(x-2)

We move all terms to the left:

6(x+3)-12-(4(x-2))=0

We multiply parentheses

6x-(4(x-2))+18-12=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

6x-(4x-8)+6=0

We get rid of parentheses

6x-4x+8+6=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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