6(x+3)-3(x+4)=4(x+2)-3(x-1)

Solution for 6(x+3)-3(x+4)=4(x+2)-3(x-1) equation:

6(x+3)-3(x+4)=4(x+2)-3(x-1)

We move all terms to the left:

6(x+3)-3(x+4)-(4(x+2)-3(x-1))=0

We multiply parentheses

6x-3x-(4(x+2)-3(x-1))+18-12=0


We calculate terms in parentheses: -(4(x+2)-3(x-1)), so:

4(x+2)-3(x-1)

We multiply parentheses

4x-3x+8+3

We add all the numbers together, and all the variables

x+11

Back to the equation:

-(x+11)


We add all the numbers together, and all the variables

3x-(x+11)+6=0

We get rid of parentheses

3x-x-11+6=0

We add all the numbers together, and all the variables

2x-5=0

We move all terms containing x to the left, all other terms to the right

2x=5

x=5/2

x=2+1/2