6(x+3)-3(x-4)=8(x-3)-6(x-5)

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Solution for 6(x+3)-3(x-4)=8(x-3)-6(x-5) equation: 



6(x+3)-3(x-4)=8(x-3)-6(x-5)

We move all terms to the left:

6(x+3)-3(x-4)-(8(x-3)-6(x-5))=0

We multiply parentheses

6x-3x-(8(x-3)-6(x-5))+18+12=0



We calculate terms in parentheses: -(8(x-3)-6(x-5)), so:

8(x-3)-6(x-5)

We multiply parentheses

8x-6x-24+30

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

3x-(2x+6)+30=0

We get rid of parentheses

3x-2x-6+30=0

We add all the numbers together, and all the variables

x+24=0

We move all terms containing x to the left, all other terms to the right

x=-24

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