6(x+3)-7=2x+4(2+x)

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Solution for 6(x+3)-7=2x+4(2+x) equation: 



6(x+3)-7=2x+4(2+x)

We move all terms to the left:

6(x+3)-7-(2x+4(2+x))=0

We add all the numbers together, and all the variables

6(x+3)-(2x+4(x+2))-7=0

We multiply parentheses

6x-(2x+4(x+2))+18-7=0



We calculate terms in parentheses: -(2x+4(x+2)), so:

2x+4(x+2)

We multiply parentheses

2x+4x+8

We add all the numbers together, and all the variables

6x+8

Back to the equation:

-(6x+8)



We add all the numbers together, and all the variables

6x-(6x+8)+11=0

We get rid of parentheses

6x-6x-8+11=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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