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6(x+3)-8=2x+10+4x
We move all terms to the left:
6(x+3)-8-(2x+10+4x)=0
We add all the numbers together, and all the variables
6(x+3)-(6x+10)-8=0
We multiply parentheses
6x-(6x+10)+18-8=0
We get rid of parentheses
6x-6x-10+18-8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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