6(x+3)=(3+x)2

Solution for 6(x+3)=(3+x)2 equation:

6(x+3)=(3+x)2

We move all terms to the left:

6(x+3)-((3+x)2)=0

We add all the numbers together, and all the variables

6(x+3)-((x+3)2)=0

We multiply parentheses

6x-((x+3)2)+18=0


We calculate terms in parentheses: -((x+3)2), so:

(x+3)2

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)


We get rid of parentheses

6x-2x-6+18=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3