6(x+3)=-3(x+1)-6

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Solution for 6(x+3)=-3(x+1)-6 equation: 



6(x+3)=-3(x+1)-6

We move all terms to the left:

6(x+3)-(-3(x+1)-6)=0

We multiply parentheses

6x-(-3(x+1)-6)+18=0



We calculate terms in parentheses: -(-3(x+1)-6), so:

-3(x+1)-6

We multiply parentheses

-3x-3-6

We add all the numbers together, and all the variables

-3x-9

Back to the equation:

-(-3x-9)



We get rid of parentheses

6x+3x+9+18=0

We add all the numbers together, and all the variables

9x+27=0

We move all terms containing x to the left, all other terms to the right

9x=-27

x=-27/9

x=-3

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