6(x+3)=10(2x+12)

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Solution for 6(x+3)=10(2x+12) equation: 



6(x+3)=10(2x+12)

We move all terms to the left:

6(x+3)-(10(2x+12))=0

We multiply parentheses

6x-(10(2x+12))+18=0



We calculate terms in parentheses: -(10(2x+12)), so:

10(2x+12)

We multiply parentheses

20x+120

Back to the equation:

-(20x+120)



We get rid of parentheses

6x-20x-120+18=0

We add all the numbers together, and all the variables

-14x-102=0

We move all terms containing x to the left, all other terms to the right

-14x=102

x=102/-14

x=-7+2/7

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