6(x+3)=2x+18+4x

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Solution for 6(x+3)=2x+18+4x equation: 



6(x+3)=2x+18+4x

We move all terms to the left:

6(x+3)-(2x+18+4x)=0

We add all the numbers together, and all the variables

6(x+3)-(6x+18)=0

We multiply parentheses

6x-(6x+18)+18=0

We get rid of parentheses

6x-6x-18+18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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