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6(x+3)=3(x-4)=24
We move all terms to the left:
6(x+3)-(3(x-4))=0
We multiply parentheses
6x-(3(x-4))+18=0
We calculate terms in parentheses: -(3(x-4)), so:We get rid of parentheses
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
6x-3x+12+18=0
We add all the numbers together, and all the variables
3x+30=0
We move all terms containing x to the left, all other terms to the right
3x=-30
x=-30/3
x=-10
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